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SiH3- Shape: Is it planar or pyramidal. e. Br2 CH2 Polar or non polar molecule? Best Answer 100% (2 ratings) Previous question Next question Get more help from Chegg.

The Center for Computational Chemistry (previously known as the Center for Computational Quantum Chemistry) at the University of Georgia seeks to develop theoretical and computational methods through mathematical models for describing and understanding the movement and function of electrons in molecules and to apply the theoretical methods to significant problems of broad chemical interest.

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The observed hyperfine structure caused by the isotopes 29Si, 73Ge, and 117,119Sn indicate that the radicals SiH3, GeH3, and SnH3 are not planar like CH3, but are pyramidal in structure.

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Both the endo- and exo-bicyclo[2.1.0]pent-2-yl radicals are significantly pyramidal, but are nearly equal in energy (Delta E < 0.3 kcal/mol) and are separated by a very low (<0.4 kcal/mol) barrier. The barrier for trapping the bicyclopentyl radical by H2S is 1.5 kcal/mol lower for the endo radical.

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N (SiH3)3 compouding is planar with an sp2 nitrogen, while the geometry of N (CH3)3 is pyramidal with an sp3 nitrogen. The planar geometry in N (SiH 3)3 is due to pp- dp bonding between a nitrogen 2p orbital and empty 3d orbitals on Si. This p-bonding decreases the Lewis basicity of N (SiH3)3 by delocalizing the nitrogen lone pair.

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Solid-state structures of [M III (N″) 3] complexes are typified by either trigonal-planar (D 3h) or trigonal-pyramidal (C 3v) geometries, with all f-block examples exhibiting the latter shape. The pyramidalization of [Ln(N″) 3 ] has been rationalized by various arguments, including involvement of n d orbitals and dispersion effects (8b, 13) and dipole stabilization by deviation of the Ln(III) cation from the N 3 plane.

PH3 has 3 bonding pairs and 1 non-bonding pair of electrons. Its electron pair geometry is Tetrahedral and its molecular geometry is Trigonal Pyramidal.

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Draw Lewis structures and give the other information requested for the following: (a) SO3. Polar or nonpolar molecule? (b) PF3. Polar or nonpolar molecule? (c) F3SiH. Show the direction of the resultant dipole moment. (d) SiH3 2. Planar or pyramidal shape? (e) Br2CH2. Polar or nonpolar molecule?

In case of N(CH3)3, PΠ-PΠ bonding occur between N and C atom.thus N has sp3 hybridisation with pyramidal shape. But in case of N(SiH3)3, pπ-dπ bonding( back bonding) occur. due to Si has vacant 3d orbital.thus N has sp2 hybridisation with planar shape.

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